Re: [ihc] ignition coil condenser

[John Hofstetter <hofs@xxxxxxxxxxxx>]

On Sep 9, 2004, at 6:02 PM, Allan Ericson wrote:

> Adding the condenser "slows down" the rate of change, but since the 
> points
> have to be open for it to affect the circuit, it only happens when they
> open. In a capacitive circuit, you can calculate the rate of 
> charge/change
> by multiplying capacitance (in farads) times resistance (in ohms) to 
> get the
> amount of time (in seconds) to reach 63% of total voltage applied. The
> condenser (capacitor) needs to be barely large enough to take enough 
> time to
> "shape" the discharging signal in a manner that allows it to transfer
> through the coil.
I hope you're paying attention, Thomas. There's a formula that you 
never know when you might need. <vbg>  Actually, I enjoy seeing 
formulas like that that kind of tie things together that otherwise seem 
unrelated. When I learned derivatives in Calculus, the laws of motion 
suddenly made sense in regard to how they related to each other.

By the way, on the yahoo site that you sent out, there was only one 
photo and it was of an old GMC version of the Blazer. I'd like to see 
the others, please.

Nice to hear from you,

John

John Hofstetter
Ol' Saline
www.goldrush.com/~hofs